a: \(=-1\cdot\dfrac{8}{3}=\dfrac{8}{3}\)
b: \(=\dfrac{5}{2}\cdot\dfrac{-3}{7}=\dfrac{-15}{14}\)
c: \(=\dfrac{27}{62}\cdot\dfrac{31}{27}=\dfrac{1}{2}\)
a) \(\left(-1\right):\dfrac{3}{8}=\dfrac{\left(-1\right).8}{3}=-\dfrac{8}{3}\)
b) \(\dfrac{5}{2}:\left(-\dfrac{7}{3}\right)=\dfrac{5}{2}.\left(\dfrac{-3}{7}\right)=-\dfrac{15}{14}\)
c) \(\left(-\dfrac{27}{62}\right):\left(-\dfrac{27}{31}\right)=\left(-\dfrac{27}{62}\right).\left(-\dfrac{31}{27}\right)=\dfrac{31}{62}=\dfrac{1}{2}\)
`a) (-1) : 3/8`
`= (-1) xx 8/3`
`=-8/3`
________________________________
`b) 5/2 : (-7/3)`
`= 5/2 xx (-3/7)`
`= -15/14`
_________________________________
`c) (-27/62) : (-27/31)`
`=(-27/62) xx (-32/27)`
`= 1/2`
`(-1) : 3/8 = (-1) xx 8/3 = (-8)/3`
`5/2 : (-7)/3 = 5/2 xx (-3/7) = (5xx(-3)/(2xx7) = -15/14`
`(-27)/62 : (-27)/31 = (-27)/62 xx (-31)/27 = (-27xx(-31)/(62xx27) = 1/2`
