\(=\dfrac{1}{\left(\sqrt{2}-\sqrt{3}\right)^2}=\dfrac{1}{2-2\sqrt{6}+3}=\dfrac{1}{5-2\sqrt{6}}=\dfrac{5+2\sqrt{6}}{\left(5-2\sqrt{6}\right)\left(5+2\sqrt{6}\right)}=\dfrac{5+2\sqrt{6}}{25-24}=\dfrac{5+2\sqrt{6}}{1}=5+2\sqrt{6}\)
\(=\dfrac{1}{5-2\sqrt{6}}=5+2\sqrt{6}\)
`(1/(sqrt 2 - sqrt 3))^2`
`= 1/(sqrt 2 - sqrt 3)^2`
`= 1/(5 - 2 sqrt 6)`