Question

  Tính giới hạn sau:

Answer 1

\(...=\lim\limits_{n\rightarrow\infty}\dfrac{\sqrt{n^2\left(4+\dfrac{3}{n^2}\right)}}{n}=\)\(\lim\limits_{n\rightarrow\infty}\dfrac{\left|n\right|\sqrt{4+\dfrac{3}{n^2}}}{n}\)

\(=\left[{}\begin{matrix}\lim\limits_{n\rightarrow+\infty}\dfrac{n\sqrt{4+\dfrac{3}{n^2}}}{n}=\dfrac{2}{1}=2\\\lim\limits_{n\rightarrow-\infty}\dfrac{-n\sqrt{4+\dfrac{3}{n^2}}}{n}=-\dfrac{2}{1}=-2\end{matrix}\right.\)