Ta có:
lim x → 2 x n + n x + n - 1 x - 1 2 = lim x → 2 x n - 1 - n x - 1 x - 1 2 = lim x → 1 x n - 1 + x n - 2 + . . + x + 1 - n x - 1 = lim x → 1 x n - 1 + x n - 2 + . . + x + 1 x - 1 = lim x → 1 x n - 1 + x n - 2 + . . + 1 + x n - 3 + x n - 4 + . . + 1 = n - 1 + n - 2 + . . + 1 = n n - 1 2 = n 2 - n 2
Đáp án C