a) => 5x=(x-1):(x-1)
=>5x=1
=>x=1/5
b)=>2x+10-x^2-5x=0
=>10-3x-x^2=0
=>10-5x+2x-x^2=0
=>5(2-x)+x(2-x)=0
=>(2-x)(5+x)=0
=> 2-x=0 hoặc 5+x=0
=> x=2 hoặc x=-5
Chúc bạn học tốt T I C K cho mình nha mình cảm ơn rất nhìu
a)\(5x\left(x-1\right)=\left(x-1\right)\)
=>\(5x\left(x-1\right)-\left(x-1\right)=0\)
=>\(\left(x-1\right)\left(5x-1\right)=0\)
=>\(\orbr{\begin{cases}x-1=0\\5x-1=0\end{cases}}\)
=>\(\orbr{\begin{cases}x=1\\x=\frac{1}{5}\end{cases}}\)
\(S=\left\{\frac{1}{5};1\right\}\)
b) \(2\left(x+5\right)-x^2-5x=0\)
=>\(2\left(x+5\right)-x\left(x+5\right)=0\)
=>\(\left(2-x\right)\left(x+5\right)=0\)
=>\(\orbr{\begin{cases}2-x=0\\x+5=0\end{cases}}\)
=>\(\orbr{\begin{cases}x=2\\x=-5\end{cases}}\)
\(S=\left\{-5;2\right\}\)
