Question

Tìmx

(2x-3)^2-2x+3=0

Giúp e với

Answer 1

I don't now

or no I don't

..................

sorry

Answer 2

\(\left(2x-3\right)^2-\left(2x-3\right)=0\)

\(\Rightarrow\left(2x-3\right)\left(2x-3-1\right)=0\)

\(\Rightarrow\left(2x-3\right)\left(2x-4\right)=0\)

\(\Rightarrow\hept{\begin{cases}2x-3=0\\2x-4=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=\frac{3}{2}\\x=2\end{cases}}\)