a) \(\left(x+5\right).\left(x-4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+5=0\\x-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0-5\\x=0+4\end{cases}\Rightarrow}\orbr{\begin{cases}x=-5\\x=+4\end{cases}}}\)
Vậy \(x\in\){-5 ; 4}
b) \(\left(x-5\right)^6=\left(x-5\right)^8\)
Ta có : \(0^n=0\)\(;\)\(1^n=1\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x-5=1\end{cases}\Rightarrow\orbr{\begin{cases}x=0+5\\x=1+5\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)
Vậy \(x\in\){5 ; 6}
a) (x + 5) . (x - 4) = 0
x + 5 = 0 x = -5
<=> <=>
x - 4 = 0 x = 4
a) \(\left(x+5\right).\left(x-4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+5=0\\x-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0-5\\x=0+4\end{cases}\Rightarrow}\orbr{\begin{cases}x=-5\\x=+4\end{cases}}}\)
Vậy \(x\in\){-5 ; 4}
b) \(\left(x-5\right)^6=\left(x-5\right)^8\)
Ta có : \(0^n=0\)\(;\)\(1^n=1\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x-5=1\end{cases}\Rightarrow\orbr{\begin{cases}x=0+5\\x=1+5\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)
Vậy \(x\in\){5 ; 6}