Question

Tìm x

\(\left(x-\dfrac{1}{5}\right).\left(1,5+2x\right)=0\)

Answer 1

TH1: \(x-\dfrac{1}{5}=0\Rightarrow x=\dfrac{1}{5}\)

TH2: \(1,5+2x=0\Rightarrow2x=-1,5\Rightarrow x=-0,75=-\dfrac{3}{4}\)

Vậy \(x=\dfrac{1}{5}\) hoặc \(x=-\dfrac{3}{4}\)

Answer 2

`(x-1/5).(1,5+2x)=0`

`Th1`

`x-1/5=0`

`=>x=0+1/5`

`=>x=1/5`

`Th2`

`1,5 + 2x=0`

`=>2x=0-1,5`

`=>2x=-1,5`

`=>x=-1,5:2`

`=>x=-0,75`

Answer 3

`->` \(\left[{}\begin{matrix}x-\dfrac{1}{5}=0\\1,5+2x=0\end{matrix}\right.\)

`->` \(\left[{}\begin{matrix}x=\dfrac{1}{5}\\2x=-1,5->x=-0,75\end{matrix}\right.\)

Answer 4

chia thành 2 trường hợp :

+ trường hợp 1 :

\(\left(x-\dfrac{1}{5}\right)=0\)

\(x=0+\dfrac{1}{5}\)

\(x=\dfrac{1}{5}\)

+ trường hợp 2 :

\(\left(1,5+2x\right)=0\)

\(2x=0-1,5\)

\(2x=-\dfrac{3}{2}\)

\(x=-\dfrac{3}{2}:2\)

\(x=-\dfrac{3}{4}\)

\(Vậyx=\dfrac{1}{5}hoặc-\dfrac{3}{4}\)