Question

Tìm \(x\in Z\), biết:

                   \(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{x\left(x+1\right)}=\frac{3}{10}\) 

Answer 1

1/3.4+1/4.5+1/5.6+.....+1/x(x+1)=3/10

1/3-1/4+1/4-1/5+1/5-........-1/x+1/x-1/x+1=3/10

=>1/3-1/x+1=3/10

   1/x+1=3/10-1/3=1/30

=>x+1=30

   x=30-1

   x=29

Answer 2

Ta có :

\(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{x\left(x+1\right)}=\frac{3}{10}\)

=>\(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{3}{10}\)

=>\(\frac{1}{3}-\frac{1}{x+1}=\frac{3}{10}\)

=>\(\frac{1}{x+1}=\frac{1}{3}-\frac{3}{10}\)

=>\(\frac{1}{x+1}=\frac{1}{30}\)

=>\(x+1=30\)

=>\(x=30-1\)

=>\(x=29\)

Vậy \(x=29\)