\(\left(\dfrac{1}{2}\right)^x+\left(\dfrac{1}{2}\right)^x+\left(\dfrac{1}{2}\right)^1=\dfrac{3}{8}\)
=>\(\left(\dfrac{1}{2}\right)^x\cdot2=\dfrac{3}{8}-\dfrac{1}{2}=-\dfrac{1}{8}\)
=>\(\left(\dfrac{1}{2}\right)^x=-\dfrac{1}{16}\)(vô lý)
=>\(x\in\varnothing\)
\(\left(\dfrac{1}{2}\right)^x+\left(\dfrac{1}{2}\right)^x+\left(\dfrac{1}{2}\right)^1=\dfrac{3}{8}\)
\(\Leftrightarrow2.\left(\dfrac{1}{2}\right)^x=-\dfrac{1}{8}\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^x=-\dfrac{1}{16}\)
=> Vô nghiệm