Question

tìm x 

Answer 1

\(\left(x^2-3x\right)\left(x^4+1\right)=0\)

\(x\left(x-3\right)\left(x^4+1\right)=0\)

\(x=0\) hoặc \(x-3=0\) hoặc \(x^4+1=0\) (ko có x thỏa mãn)

\(x=0\) hoặc \(x=3\)

Answer 2

\(\left(x^2-3x\right)\left(x^4+1\right)=0\left(1\right)\)

vì \(x^4+1>0,\forall x\in R\)

\(\left(1\right)\Rightarrow x^2-3x=0\)

\(\Rightarrow x\left(x-3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x-3=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)