\(2^3x+5^2x=2.\left(5^2+2^3\right)-33\)
\(8x+25x=2.\left(25+8\right)-33\)
\(8x+25x=2.33-33\)
\(8x+25x=66-33\)
\(8x+25x=33\)
\(x+\left(8+25\right)=33\)
\(x+33=33\)
\(x=0\)
\(15:\left(x+2\right)=\left(3^3+3\right):10\)
\(15:\left(x+2\right)=\left(27+3\right):10\)
\(15:\left(x+2\right)=30:10\)
\(15:\left(x+2\right)=3\)
\(x+2=15:3\)
\(x+2=5\)
\(x=3\)
Ta có: \(15:\left(x+2\right)=\left(3^3+3\right):10\)
\(\Leftrightarrow15:\left(x+2\right)=3\)
\(\Leftrightarrow x+2=5\)
hay x=3