\(Sửa:\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2-2\right)=15\\ \Leftrightarrow x^3+8-x^3+2x=15\\ \Leftrightarrow2x=7\Leftrightarrow x=\dfrac{7}{2}\)
Tìm x biết : a) (x+2)(x²-2x+4)-x(x²-2)=15 b) (x-4)² - (x-2)(x+2)= 6 c) x⁴-2x³+x²-2x=0
tìm x biết
a x^2 (2x+15)+4(2x+15)=0
b 5x(x-2)-3(x-2)=0
c 2(x+3)-x^2-3x=0
Bài 2: Tìm x, biết: a) (x+2)(x² -2x+4)-x(x²+2)=15 b) (x-2)³-(x-4)(x² + 4x+16) + 6(x+1)=49 c) (x - 1)³ + (2 - x)(4 + 2x + x²)+ 3x(x + 2) = 16 d) (x - 3)³ - (x - 3)(x² + 3x + 9) + 9(x + 1)² = 15
Tìm x biết:
a) ( x – 1 ) 3 + ( 2 – x ) ( 4 + 2 x + x 2 ) + 3x(x + 2) = 16;
b) (x + 2)( x 2 – 2x + 4) – x( x 2 – 2) = 15.
tìm x biết:(x+2).(x^2-2x+4)-x.(x^2-2)=15
Tìm x
A) (x+2)(x^2-2x+4)-x(x^2-2)=15
B) (x-1)^3+(2-x)(4-2x+x^2)+3x(x+2)=17
Thank kiu trước nha
TÌM X:
A)(X+2)(X^2-2X+4)+X(X^2+2)=15
tìm GTLN
C=\(\dfrac{16-3x^2+5x}{4}\)
D=\(\dfrac{15}{x^2-2x+4}\)
E=\(\dfrac{x^2-2x+2015}{x^2}\)
Tìm x)
a) (x+2)(x2-2x+4)-x(x2+2)=15
