Question

Tìm x trong tỉ lệ thức sau: x/3,15=0,15/7,2

Answer 1

Ta có:

`x/3,15=0,15/7,2`

`⇒7,2x=3,15.0,15`

`⇒7,2x=0,4725`

`⇒x=0,4725:7,2`

`⇒x=21/320`

Answer 2

\(\dfrac{x}{3.15}=\dfrac{0.15}{7.2}=\dfrac{1}{48}\)

nên \(x=\dfrac{1}{48}\cdot3.15=\dfrac{21}{320}\)

Answer 3

`x/3,15=0,15/7,2`

`⇒7,2x=3,15.0,15`

`⇒7,2x=0,4725`

`⇒x=0,4725:7,2`

`⇒x=21/320`

Answer 4

\(\dfrac{x}{3,15}=\dfrac{0.15}{7,2}\)

\(=\dfrac{x}{3,15}=\dfrac{0.15}{7,2}=\dfrac{1}{48}\)

\(=\dfrac{x}{3,15}=\dfrac{1}{48}\)

\(=x:3,15=\dfrac{1}{48}\)

\(x=\dfrac{1}{48}\times3,15=\dfrac{21}{320}\)

Vậy `x = 21/320`

Answer 5