Question

tìm x thuộc z để 4x²-6x-16 chia hết cho x-3

Answer 1

\(4x^2-6x-16⋮x-3\)

\(\Leftrightarrow4x^2-12x+6x-18+2⋮x-3\)

\(\Leftrightarrow4x\left(x-3\right)+6\left(x-3\right)+2⋮x-3\)

\(\Leftrightarrow\left(x-3\right)\left(4x+6\right)+2⋮x-3\)

Mà \(\left(x-3\right)\left(4x+6\right)⋮x-3\)

\(\Rightarrow2⋮x-3\)

\(\Rightarrow x-3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)

làm nốt

Answer 2

cách 2:

Để \(4x^2-6x-16\)chia hết cho x-3 

\(\Leftrightarrow2⋮x-3\)

\(\Leftrightarrow x-3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)

Làm nốt