Question

tìm x, biết:

x³-13x=0

Answer 1

\(\Leftrightarrow x\cdot\left(x-\sqrt{13}\right)\left(x+\sqrt{13}\right)=0\)

hay \(x\in\left\{0;\sqrt{13};-\sqrt{13}\right\}\)

Answer 2

\(x\left(x^2-13\right)=0\)

\(\left[{}\begin{matrix}x=0\\x^2-13=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=0\\\left[{}\begin{matrix}x=\sqrt{13}\\x=-\sqrt{13}\end{matrix}\right.\end{matrix}\right.\)