Question

tìm x , biết:

(x-2)² - 4x + 8 =0

Answer 1

(x-2)^2-4x+8=0

=>(x-2)^2-4(x-2)=0

=>(x-2)(x-2-4)=0

=>(x-2)(x-6)=0

=>x=2 hoặc x=6

Answer 2

`(x-2)^2 -4x+8=0`

`<=> (x-2)^2 -(4x-8)=0`

`<=> (x-2)^2 - 4(x-2)=0`

`<=> (x-2)(x-2-4)=0`

`<=>(x-2)(x-6)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)