a) \(3\left(x-2\right)+2\left(x-3\right)=5\)
\(\Rightarrow3x-6+2x-6=5\)
\(\Rightarrow5x=17\Rightarrow x=\dfrac{17}{5}\)
b) \(\left(2x-8\right)^2-16=0\)
\(\Rightarrow\left(2x-8-4\right)\left(2x-8+4\right)=0\)
\(\Rightarrow\left(2x-12\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x=12\\2x=4\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=6\\x=2\end{matrix}\right.\)
c) \(\left(2x-1\right)^2-\left(4x+1\right)\left(x-3\right)=3\)
\(\Rightarrow4x^2-4x+1-4x^2+12x-x+3=3\)
\(\Rightarrow7x=-1\Rightarrow x=-\dfrac{1}{7}\)
a: Ta có: \(3\left(x-2\right)+2\left(x-3\right)=5\)
\(\Leftrightarrow3x-6+2x-6=5\)
\(\Leftrightarrow5x=17\)
hay \(x=\dfrac{17}{5}\)
b: Ta có: \(\left(2x-8\right)^2-16=0\)
\(\Leftrightarrow\left(2x-4\right)\left(2x-12\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=6\end{matrix}\right.\)
a. \(3\left(x-2\right)+2\left(x-3\right)=5\)
\(\Leftrightarrow3x-6+2x-6=5\)
\(\Leftrightarrow5x=17\)
\(\Leftrightarrow x=\dfrac{17}{5}\)
b. \(\left(2x-8\right)^2-16=0\)
\(\Leftrightarrow\left(2x-8-4\right)\left(2x-8+4\right)=0\)
\(\Leftrightarrow4\left(x-6\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-6=0\\x-2=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=2\end{matrix}\right.\)
c. \(\left(2x-1\right)^2-\left(4x+1\right)\left(x-3\right)=3\)
\(\Leftrightarrow4x^2-4x+1-4x^2+11x+3-3=0\)
\(\Leftrightarrow7x+1=0\)
\(\Leftrightarrow x=-\dfrac{1}{7}\)
c: Ta có: \(\left(2x-1\right)^2-\left(4x+1\right)\left(x-3\right)=3\)
\(\Leftrightarrow4x^2-4x+1-4x^2+12x-x+3=3\)
\(\Leftrightarrow7x=-1\)
hay \(x=-\dfrac{1}{7}\)
