Question

Tìm x biết x²-8x+12=0

Answer 1

x = 2 hoặc = 6

Cách làm:

x² - 8x + 12 = 0

x² - 6x - 2x + 12 = 0

( x² - 6x ) - ( 6x - 12 ) = 0

x . ( x - 2 ) - 6 . ( x - 2 ) = 0

( x - 2 ) . ( x - 6 ) = 0

\(\Rightarrow\hept{\begin{cases}x-2=0\\x-6=0\end{cases}}\hept{\begin{cases}x=2\\x=6\end{cases}}\)

Answer 2

x²-8x+12=0

<=> x²-6x-2x+12=0

<=> (x²-2x)-(6x-12)=0

<=> x.(x-2)-6.(x-2)=0

<=> (x-2)(x-6)=0

<=>\(\orbr{\begin{cases}x-2=0\\x-6=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=6\end{cases}}\)

Answer 3

\(=x^2-2x-6x+12\)

\(=x\left(x-2\right)-6\left(x-2\right)\)

\(=\left(x-2\right)\left(x-6\right)\)

Answer 4

ban kia lam dung roi do

k tui nha

thanks

Answer 5

Cả 2 bn đều làm đúng rồi k cho mk nha bn