`(x+3)/(x-4) = 5/7` ( `x≠ 4)`
`=> 7*(x+3) = 5*(x-4)`
`=> 7x + 21 = 5x - 20`
`=> 7x - 5x = -21 - 20`
`=> 2x = -41`
`=> x = -41/2`(thỏa mãn dkxd)
Vậy `x= -41/2`
tìm x biết
\(\dfrac{x-2}{x-3}\)=\(\dfrac{x+4}{x-2}\)
(với x ≠ 2 , x ≠ 3
Tìm x,y biết:
\(\dfrac{x}{4}=\dfrac{2y+1}{3}=\dfrac{x-2y-1}{y}\)(với \(y\ne0\))
1, Tìm x ∈ Z biết
a, \(\dfrac{x-4}{15}\)=\(\dfrac{5}{3}\)
b, \(\dfrac{x}{4}\)=\(\dfrac{18}{x+1}\)
c,2x+3 ⋮ x+4
\sqrt{1} \(\dfrac{help}{me}\)
Giúp mình vớiiiii ! Mình cảm ơn !
Tìm x,y biết : \(\dfrac{x}{4}\) = \(\dfrac{2y+1}{3}\) = \(\dfrac{x-2y-1}{y}\) ( với y ≠ 0 )
Tìm x biết : \(\dfrac{x+4}{2014}\)+\(\dfrac{x+3}{2015}=\dfrac{x+2}{2016}+\dfrac{x+1}{2017}\)
Bài 2. Tìm x biết
\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
tìm x \(\in\) Q biết rằng
\(\dfrac{11}{12}\) - ( \(\dfrac{2}{5}\) + x ) = \(\dfrac{2}{3}\)
2x \(\times\) ( x - \(\dfrac{1}{7}\) ) = 0
\(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) : x = \(\dfrac{2}{5}\)
Tìm x∈Z biết
\(\dfrac{x+4}{2008}+\dfrac{x+3}{2007}=\dfrac{x+2}{2009}+\dfrac{x+1}{2010}\)
Tìm x, biết:
a) \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\)x = \(\left(-\dfrac{7}{12}\right)\) . \(1\dfrac{2}{5}\)
b) \(\left(\dfrac{1}{5}-\dfrac{3}{2}x\right)^2\) = \(\dfrac{9}{4}\)
c) (1,25 - \(\dfrac{4}{5}\)x)3 = -125
