Question

tìm x biết \(\dfrac{-1}{8}< \dfrac{x}{72}\le\dfrac{-1}{36}\left(vớix\in z\right)\)

Answer 1

\(-\dfrac{1}{8}< \dfrac{x}{72}\le-\dfrac{1}{36}\)
\(\Rightarrow\dfrac{-9}{72}< \dfrac{x}{72}\le-\dfrac{2}{72}\)
\(\Rightarrow x\in\left\{-8;-7;-6;-5;-4;-3;-2\right\}\)

Answer 2

`(-1)/8 < x/72 <= (-1)/36`

`(-1xx9)/(8xx9) < x/72 <=  (-1xx2)/(36xx2)`

`(-9)/72 < x/72 <=   (-2)/72`

`-> -9< x <=   (-2)`

`-> x=-8;-7;-6;-5;-4;-3;-2`

`@ yngoc`

Answer 3