Question

Tìm x biết :

a) x−53 +x−517 +x−519 =0

b)x+1015 +x−1035 +x−1237 =−3

c) x+120 +x+219 +x+318 =x+417 +x+516 +x+615 

d) x−215 +x−512 

Answer 1

a) \(x-53+x-527+x-519=0\\ \Rightarrow3x-1099=0\\ \Rightarrow x=\dfrac{1099}{3}\)

b) \(x+1015+x-1035+x-1237=-3\\ \Rightarrow3x-1257=-3\\ \Rightarrow3x=-1260\\ \Rightarrow x=-420\)

c) \(x+120+x+129+x+318=x+417+x+516+x+615\\ \Rightarrow x+120+x+129+x+318-x-417-x-516-x-615=0\\ \Rightarrow-981=0\left(vôlí\right)\)

Answer 2

a. x - 53 + x - 517 + x - 519 = 0

<=> x + x + x = 519 + 517 + 53

<=> 3x = 1089

<=> x = 363

b. x + 1015 + x - 1035 + x - 1237 = -3

<=> x + x + x = -3 - 1015 + 1035 + 1237

<=> 3x = 1254

<=> x = 418

c. x + 120 + x 219 + x + 318 = x + 417 + x + 516 + x + 615

<=> x + x - x - x - x = 417 + 516 + 615 - 120 - 219 - 318

<=> -x = 891

<=> x = -891

d. Ko có kết quả ko tìm đc x nha bn, bn xem lại đề rồi nhắc mik.

Answer 3

a: Ta có: \(x-53+x-517+x-519=0\)

\(\Leftrightarrow3x=1089\)

hay x=363

b: Ta có: \(x+1015+x-1035+x-1237=-3\)

\(\Leftrightarrow3x=-1260\)

hay x=-420