3^x+3^(x+1)+3^(x+2)=1053 <=> 3^x+3^1*3^x+3^2*3^x=1053
<=> (1+3^1+3^2)*3^x=1053
<=>3^x= 1053/ (1+3+9)
<=> 3^x=81
=> x=4
3x+2+3x+1+3x=1053
=> 3x.(32+3+1)=1053
=> 3x.13=1053
=> 3x=1053:13
=> 3x=81
=> 3x=34
Vậy x=4.
\(3^{x+2}+3^{x+1}+3^x=1053\) => \(3^x\left(3^2+3+1\right)=1053\Leftrightarrow3^x.13=1053\)
\(3^x=81\Leftrightarrow3^x=3^4\Leftrightarrow x=4\)