Question

Tìm x biết : ( 3x + 1). ( 2x- 3) - 6x. (x + 2) = 16

Answer 1

\(\left(3x+1\right)\left(2x-3\right)-6x\left(x+2\right)=16\)

=>\(6x^2-9x+2x-3-6x^2-12x=16\)

=>-19x=19

=>x=-1

Answer 2

Ta có:

( 3x + 1). ( 2x- 3) - 6x. (x + 2) = 16

3x ( 2x -3)+ 1.(2x – 3 ) - 6x. x – 6x . 2 = 16

6x^2 – 9x + 2x – 3 – 6x^2 - 12x = 16

-19x = 16 + 3

- 19x = 19

x = - 1

Answer 3

`(3x + 1)(2x - 3) - 6x(x + 2) = 16`

`6x^2 - 9x + 2x - 3 - 6x^2 - 12x = 16`

`-9x + 2x - 12x - 3 = 16`
`-19x - 3 = 16`

`-19x = 19`

`x = -1`
 

Answer 4

`(3x + 1)(2x - 3) - 6x(x + 2) = 16`

`=>6x^2 - 9x + 2x - 3 - 6x^2 - 12x = 16`

`=>-9x + 2x - 12x - 3 = 16`
`=>-19x - 3 = 16`

`=>-19x = 19`

`=>x = -1`