Question

Tìm x (8)^n-1=(16)^2

Answer 1

\(8^{n-1}=16^2\)

\(\Rightarrow\left(2^3\right)^{n-1}=\left(2^4\right)^2\)

\(\Rightarrow2^{3\left(n-1\right)}=2^8\)

\(\Rightarrow2^{3n-3}\)

\(\Rightarrow3n-3=8\)

\(\Rightarrow3n=8+3\)

\(\Rightarrow3n=11\)

\(\Rightarrow n=\dfrac{11}{3}\)

Answer 2

=>2^(3n-3)=2^8

=>3n-3=8

=>3n=11

=>n=11/3