Question

tìm x:

3^x-1 + 3^x + 3^x+1 = 39

giúp mik với ;-;

 

Answer 1

\(3^{x-1}+3^x+3^{x+1}=39\)

\(3^{x-1}+3^{x-1}.3+9.3^{x-1}=39\)

\(13.3^{x-1}=39\)

\(3^{x-1}=39:13=3\)

\(x-1=1\)

\(x=2\)

Answer 2

Sửa đề: 3ˣ⁻¹ + 3ˣ + 3ˣ⁺¹ = 39

3ˣ⁻¹ + 3ˣ + 3ˣ⁺¹ = 39

3ˣ⁻¹.(1 + 3 + 3²) = 39

3ˣ⁻¹ . 13 = 39

3ˣ⁻¹ = 39 : 13

3ˣ⁻¹ = 3

x - 1 = 1

x = 1 + 1

x = 2