\(2x-1⋮x+5\)
\(\Rightarrow2x-1-2\left(x+5\right)⋮x+5\)
\(\Rightarrow-11⋮x+5\)
\(\Rightarrow x+5\inƯ\left(11\right)=\left\{\pm1;\pm11\right\}\)
| x+5 | -11 | -1 | 1 | 11 |
| x | -16 | -6 | -4 | 6 |
Vậy \(x\in\left\{-16;-6;-4;6\right\}\)
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Ta có: \(2x-1⋮x+5\)
\(\Leftrightarrow-11⋮x+5\)
\(\Leftrightarrow x+5\in\left\{1;-1;11;-11\right\}\)
hay \(x\in\left\{-4;-6;6;-16\right\}\)
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