a) \(\left(x-6\right)^2=9=3^2\)
\(\Rightarrow x-6=3\) hay \(x-6=-3\)
\(\Rightarrow x=9\) hay \(x=3\)
b) \(4^{2x-6}=1=4^0\)
\(\Rightarrow2x-6=0\Rightarrow x=3\)
a) \(\left(x-6\right)^2=9\)
\(\Rightarrow\left(x-6\right)^2=3^2\)
\(\Rightarrow\left[{}\begin{matrix}x-6=-3\\x-6=3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=6\\x=9\end{matrix}\right.\)
b) \(4^{2x-6}=1\)
\(\Rightarrow4^{2x-6}=4^0\)
\(\Rightarrow2x-6=0\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
a) Ta có ( x - 6 )2 = 9 = ( \(\pm3\) )2
Nếu ( x - 6 )2 = 32 ⇒ x = 9
Nếu ( x - 6 )2 = ( -3 )2 ⇒ x = 3
Vậy x ϵ { 9; 3 }
b) Ta có 42x - 6 = 1 = 40 ⇒ 2x - 6 = 0 ⇒ x = 3
a/
\(\left(x-6\right)^2=9\)
\(\Rightarrow\left(x-6\right)=\pm3\Rightarrow\left[{}\begin{matrix}x=9\\x=3\end{matrix}\right.\)
b/
\(4^{2x-6}=1\)
\(\Leftrightarrow4^{2x-6}=4^0\Rightarrow2x-6=0\Rightarrow x=3\)
