Question

tìm số nguyên x, biết:

Answer 1

q: \(\dfrac{-30}{x}=\dfrac{6}{-13}\)

=>\(\dfrac{30}{x}=\dfrac{6}{13}\)

=>\(x=30\cdot\dfrac{13}{6}=\dfrac{30}{6}\cdot13=5\cdot13=65\)

r: \(\dfrac{2}{7}=\dfrac{x}{56}\)

=>\(x=56\cdot\dfrac{2}{7}=\dfrac{56}{7}\cdot2=8\cdot2=16\)

Answer 2

q) \(\dfrac{-30}{x}=\dfrac{6}{-13}\)

\(\Rightarrow x=-30:\dfrac{6}{-13}\)

\(\Rightarrow x=-30\cdot\dfrac{-13}{6}\)

\(\Rightarrow x=65\left(tm\right)\)

Vậy: \(x=65\).

r) \(\dfrac{2}{7}=\dfrac{x}{56}\)

\(\Rightarrow x=\dfrac{2}{7}\cdot56\)

\(\Rightarrow x=16\left(tm\right)\)

Vậy: \(x=16\).