Ta có : 2x2 - 6x
= \(\left(\sqrt{2}x\right)^2-2.\sqrt{2}x.6+36-36\)
Q\(=\left(\sqrt{2}x-6\right)^2-36\)
Vì \(\left(\sqrt{2}x-6\right)^2\ge0\forall x\)
Nên : Q = \(=\left(\sqrt{2}x-6\right)^2-36\) \(\ge-36\forall x\)
Vậy \(Q_{min}=-36\) khi \(\sqrt{2}x-6=0\) => \(\sqrt{2}x=6\) => \(x=6:\sqrt{2}=3\sqrt{2}\)