xy-3x+y=-4
=>x(y-3)+y-3=-4-3
=>(x+1)(y-3)=-7
=>\(\left(x+1;y-3\right)\in\left\{\left(1;-7\right);\left(-7;1\right);\left(-1;7\right);\left(1;-7\right)\right\}\)
=>\(\left(x;y\right)\in\left\{\left(0;-4\right);\left(-8;4\right);\left(-2;10\right);\left(0;-4\right)\right\}\)