Question

Tìm các số tự nhiên x,y biết

(x+1) . (y-2) = 10

Answer 1

\(\Leftrightarrow\left(x+1;y-2\right)\in\left\{\left(1;10\right);\left(2;5\right);\left(5;2\right);\left(10;1\right)\right\}\)

hay \(\left(x,y\right)\in\left\{\left(0;12\right);\left(1;7\right);\left(4;4\right);\left(9;3\right)\right\}\)

Answer 2

(x+1).(y-2)=10

10=10.1=2.5

ta lập bảng

x	2	5	10	1
y	5	2	1	10
x+1	1	4	9	0
y-2	7	4	3	12