Question

tìm các số a,b,c biết :

\(3a=\dfrac{b}{\dfrac{2}{5}}=\dfrac{8c}{3}\)  và 6a + 5b + 16c = 10

Answer 1

\(3a=\dfrac{b}{\dfrac{2}{5}}=\dfrac{8c}{3}\Rightarrow\dfrac{6a}{2}=\dfrac{5b}{\dfrac{2}{5}\cdot5}=\dfrac{16c}{6}\\ \Rightarrow\dfrac{6a}{2}=\dfrac{5b}{2}=\dfrac{16c}{6}\)

Áp dụng t/c dtsbn:

\(3a=\dfrac{b}{\dfrac{2}{5}}=\dfrac{8c}{3}=\dfrac{6a}{2}=\dfrac{5b}{2}=\dfrac{16c}{6}=\dfrac{6a+5b+16c}{2+2+6}=\dfrac{10}{10}=1\\ \Rightarrow\left\{{}\begin{matrix}a=\dfrac{1}{3}\\b=\dfrac{2}{5}\\c=\dfrac{3}{8}\end{matrix}\right.\)