Ta có:
$a \div b = -3 \div 2 = \dfrac{a}{b} = \dfrac{-3}{2} => \dfrac{a}{-3} = \dfrac{b}{2}$
Áp dụng tc dãy tỉ số bằng nhau ta có:
$\dfrac{a}{-3} = \dfrac{b}{2} = \dfrac{a - b}{-3-2} = \dfrac{-10}{-5} =2$
`=> a/-3=b/2=2`
`=> a=-6; b=4`
\(a-b=10\)
\(\dfrac{a}{b}=\dfrac{-3}{2}\Rightarrow\dfrac{a}{-3}=\dfrac{b}{2}=\dfrac{a-b}{-3-2}=\dfrac{10}{-5}=-2\)
\(\Rightarrow a=\left(-3\right).\left(-2\right)=6\)
\(\Rightarrow b=6-10=-4\)
Vậy \(\left(a;b\right)\in\left\{6;-4\right\}\)
Đính chính
\(a-b=-10\)
...\(\dfrac{a}{-3}=\dfrac{b}{2}=\dfrac{a-b}{-3-2}=\dfrac{-10}{-5}=2\Rightarrow a=\left(-3\right).2=-6\Rightarrow b=-6+10=4\)
Vậy \(\left(a;b\right)\in\left\{-6;4\right\}\)