Question

tìm a,b biết a-b = -10 và a:b = -3:2

Answer 1

Ta có:

$a \div b = -3 \div 2 = \dfrac{a}{b} = \dfrac{-3}{2} => \dfrac{a}{-3} = \dfrac{b}{2}$

Áp dụng tc dãy tỉ số bằng nhau ta có:

$\dfrac{a}{-3} = \dfrac{b}{2} = \dfrac{a - b}{-3-2} = \dfrac{-10}{-5} =2$

`=> a/-3=b/2=2`

`=> a=-6; b=4`

Answer 2

\(a-b=10\)

\(\dfrac{a}{b}=\dfrac{-3}{2}\Rightarrow\dfrac{a}{-3}=\dfrac{b}{2}=\dfrac{a-b}{-3-2}=\dfrac{10}{-5}=-2\)

\(\Rightarrow a=\left(-3\right).\left(-2\right)=6\)

\(\Rightarrow b=6-10=-4\)

Vậy \(\left(a;b\right)\in\left\{6;-4\right\}\)

Answer 3

Đính chính

\(a-b=-10\)

...\(\dfrac{a}{-3}=\dfrac{b}{2}=\dfrac{a-b}{-3-2}=\dfrac{-10}{-5}=2\Rightarrow a=\left(-3\right).2=-6\Rightarrow b=-6+10=4\)

Vậy \(\left(a;b\right)\in\left\{-6;4\right\}\)