\(=\dfrac{2}{3}+\dfrac{1}{5}-\dfrac{2}{3}-4\)
\(=\dfrac{1}{5}-4=\dfrac{-19}{5}\)
\(=\dfrac{2}{3}+\dfrac{1}{5}-\dfrac{2}{3}-4\)
\(=\dfrac{1}{5}-4=\dfrac{-19}{5}\)
\(\dfrac{\text{3}}{17}\text{+}\dfrac{\text{\text{-}5}}{\text{1}\text{3}}\text{+}\dfrac{\text{1}\text{8}}{\text{3}\text{5}}\text{+}\dfrac{\text{14}}{\text{17}}\text{+}\dfrac{\text{17}}{\text{\text{-}35}}\text{+}\dfrac{\text{ }\text{-}\text{8}}{\text{\text{1}\text{3}}}\)=?
\(\dfrac{\text{\text{ }\text{-}\text{3}}}{\text{8}}\text{+}\dfrac{\text{1}\text{2}}{\text{25}}\text{+}\dfrac{\text{5}}{\text{-8}}\text{+}\dfrac{\text{2}}{\text{-5}}\text{+}\dfrac{\text{1}\text{3}}{\text{25}}\text{=}\text{?}\)\(\text{ }\text{(}\dfrac{\text{9}}{\text{1}\text{6}}\text{+}\dfrac{\text{8}}{\text{-27}}\text{)}\text{+}\text{(}\text{1}\text{+}\dfrac{\text{7}}{\text{16}}\text{+}\dfrac{\text{-}\text{1}\text{9}}{\text{27}}\text{=}\text{?}\)
\(\dfrac{\text{4}\text{2}}{\text{46}}\text{+}\dfrac{\text{2}\text{5}\text{0}}{\text{2}\text{8}\text{6}}\dfrac{\text{-}\text{2}\text{1}}{\text{2}\text{3}\text{2}}\text{+}\dfrac{\text{-}\text{143143}}{\text{143143}}\text{=}\text{?}\)
Mọi người giúp mình với mình sắp thi rồi còn 1 ngãy nữa thôi
\(\text{|}\dfrac{5}{4}x-\dfrac{7}{2}\text{|}-\text{|}\dfrac{5}{8}x+\dfrac{3}{5}\text{|}\text{=}0\)
\(\text{|}\dfrac{7}{5}x+\dfrac{2}{3}\text{|}\text{=}\text{|}\dfrac{4}{3}x-\dfrac{1}{4}\text{|}\)
\(\dfrac{-7}{x}\text{=}\dfrac{-21}{x-34}\) \(\dfrac{4-x}{-5}\text{=}\dfrac{-5}{4-x}\)
\(\dfrac{3}{x+2}\text{=}\dfrac{5}{2x+1}\) \(\dfrac{1}{2}\text{=}\dfrac{x+1}{3x}\)
\(\dfrac{-3}{x+1}\text{=}\dfrac{4}{2-2x}\)
a,\(\dfrac{x}{-3}\text{=}\dfrac{-5}{15}\) b,\(\dfrac{1173}{x}\text{=}\dfrac{3}{5}\)
c,\(\dfrac{2}{x}\text{=}\dfrac{y}{15}\text{=}\dfrac{-25}{75}\)
Bài 1: Thực hiện phép tính.
D = \(\dfrac{6^{12}+15\text{×}2^{12}\text{×}3^{11}}{12\text{×}6^{11}+7\text{×}8^4\text{×}27^4}\)
Bài 2: Tìm x,y ∈ N biết:
a) 7 × 3x + 15 = 78
b) (3x - 2)3 - 11 = 53
c) (x + 3)4 bé hơn hoặc bằng 80
d) 7 × 5x + 1 - 3.5x + 1 = 860
e) 2x + 24 = 5y
\(\text{Tìm x, biết:}\)
\(a\)) \(20\text{%}x-x+\dfrac{1}{5}=\dfrac{3}{4}\)
\(b\)) \(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\)
\(c\)) \(\left(x-\dfrac{3}{4}\right)\left(4+3x\right)=0\)
\(d\)) \(x-\dfrac{1}{3}x+\dfrac{1}{5}x=\dfrac{-26}{5}\)
\(e\)) \(50\text{%}x+\dfrac{2}{3}x=x-5\)
\(g\)) \(\dfrac{2}{3}\left(x+\dfrac{9}{5}\right)-\dfrac{3}{10}.\left(5x-\dfrac{1}{3}\right)=\dfrac{7}{15}\)
\(\text{Thực hiện phép tính một cách hợp lí:}\)
\(\dfrac{2}{5}.\dfrac{1}{3}-\dfrac{2}{15}:\dfrac{1}{5}+\dfrac{3}{5}.\dfrac{1}{3}\) \(\left(4-\dfrac{5}{12}\right):2+\dfrac{5}{24}\)
So sánh các phân số sau:
a, \(\dfrac{-11}{-32}\) và \(\dfrac{\text{16}}{\text{49}}\)
b, \(\dfrac{\text{- 2020 }}{\text{-2021}}\) và \(\dfrac{\text{-2021}}{\text{2022}}\)