\(\dfrac{4-x}{-5}=\dfrac{-5}{4-x}\)
\(\left(4-x\right)^2=25=5^2=\left(-5\right)^2\)
4-x=5 hoặc 4-x=-5
x=-1 hoặc x=9
\(\text{Tìm x, biết:}\)
\(a\)) \(20\text{%}x-x+\dfrac{1}{5}=\dfrac{3}{4}\)
\(b\)) \(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\)
\(c\)) \(\left(x-\dfrac{3}{4}\right)\left(4+3x\right)=0\)
\(d\)) \(x-\dfrac{1}{3}x+\dfrac{1}{5}x=\dfrac{-26}{5}\)
\(e\)) \(50\text{%}x+\dfrac{2}{3}x=x-5\)
\(g\)) \(\dfrac{2}{3}\left(x+\dfrac{9}{5}\right)-\dfrac{3}{10}.\left(5x-\dfrac{1}{3}\right)=\dfrac{7}{15}\)
\(\text{|}\dfrac{7}{5}x+\dfrac{2}{3}\text{|}\text{=}\text{|}\dfrac{4}{3}x-\dfrac{1}{4}\text{|}\)
\(\text{|}\dfrac{5}{4}x-\dfrac{7}{2}\text{|}-\text{|}\dfrac{5}{8}x+\dfrac{3}{5}\text{|}\text{=}0\)
\(\)\(\text{Tìm x:}\)
a) \(x+\dfrac{1}{2}=2\)
b) \(75\%x-\dfrac{1}{2}=-1\dfrac{1}{4}\)
c) \(\left|x-\dfrac{2}{5}\right|+\dfrac{7}{10}=3\)
Tìm x, biết :
a) \(\dfrac{\text{x}}{3}\) = \(\dfrac{2}{3}\) + \(\dfrac{-1}{7}\)
b) \(\dfrac{-5}{6}-x\) = \(\dfrac{7}{12}+\dfrac{-1}{3}\)
a,\(\dfrac{x}{-3}\text{=}\dfrac{-5}{15}\) b,\(\dfrac{1173}{x}\text{=}\dfrac{3}{5}\)
c,\(\dfrac{2}{x}\text{=}\dfrac{y}{15}\text{=}\dfrac{-25}{75}\)
B1: Tìm x:
1/ \(\dfrac{x+3}{15}\) = \(\dfrac{1}{3}\) - \(\dfrac{1}{15}\)
2/ (2x - 5) = (x - 3) = 0
3/ (3x - 4) - (2x - 5) = 3
4/ (2x + 1) x (\(\dfrac{1}{2}\)x - 1) = 0
a) \(\dfrac{12}{16}\) = \(\dfrac{-x}{4}\) = \(\dfrac{21}{y}\) = \(\dfrac{z}{80}\)
b) \(\dfrac{1}{3}\) x + \(\dfrac{2}{5}\) ( x - 1 ) = 0
c) ( 2x - 3 )( 6 - 2x ) = 0
d) \(\dfrac{-2}{3}\) - \(\dfrac{1}{3}\) ( 2x - 5 ) = \(\dfrac{3}{2}\)
e) 2 |\(\dfrac{1}{2}\) x - \(\dfrac{1}{3}\) | - \(\dfrac{1}{4}\)
x \(\dfrac{2}{3}\)=\(\dfrac{1}{5}\)
\(\dfrac{2}{x}\)=\(\dfrac{12}{5}\)
\(\dfrac{1}{2}\)x-\(\dfrac{3}{5}\)=\(\dfrac{-4}{5}\)
3x+2x=-5,05
