\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+2=\dfrac{1}{9}\end{matrix}\right.\Leftrightarrow x=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+2=\dfrac{1}{9}\end{matrix}\right.\Leftrightarrow x=2\)
1) x-\(7\sqrt{x-3}\) -9=0 2) \(\sqrt{x+3}\) =5-\(\sqrt{x-2}\) 3) \(\sqrt{x-4\sqrt{x+4}}\) =3 4) \(\sqrt{8-\dfrac{2}{3}x}-5\sqrt{2}\) =0 5) \(\sqrt{x^2-4x+4}\) =2-x
Giải các phương trình sau :
1/\(\sqrt{x+2+4\sqrt{x-2}}=5\)
2/\(\sqrt{x+3+4\sqrt{x-1}}=2\)
3/\(\sqrt{x+\sqrt{2x-1}}=\sqrt{2}\)
4/\(\sqrt{x-2+\sqrt{2x-5}}=3\sqrt{2}\)
Cho 0<x<2. Chứng minh rằng:
\(\dfrac{4-\sqrt{4-x^2}}{\sqrt{\left(2+x\right)^3}+\sqrt{\left(2-x\right)^3}}\) + \(\dfrac{4+\sqrt{4-x^2}}{\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}}\) = \(\dfrac{\sqrt{2+x}}{x}\)
1,\(\sqrt{x-5}+\sqrt{x+4}=3\)
2,\(\sqrt{x+4-4\sqrt{x}}+\sqrt{x+6-6\sqrt{x}}=1\)
3,\(\sqrt{x+3}-\sqrt{x-4}=1\)
4,\(\sqrt{15-x}+\sqrt{3-x}=6\)
5,\(\sqrt{10-x}+\sqrt{x+3}=5\)
6,\(\sqrt{2x-1}+\sqrt{x-2}=\sqrt{x+1}\)
7,\(\sqrt{x+6-4\sqrt{x+2}}+\sqrt{x+11-6\sqrt{x+2}}=1\)
8,\(\sqrt{x^2-5x+6}+\sqrt{x-2-3\sqrt{x-3}}=3\)
9,\(2x^2-x+4=2\sqrt{2x+3}\)
1\(\sqrt{5+2\sqrt{8}}-\sqrt{5-2\sqrt{8}}\) 2)\(\dfrac{\sqrt{x^2+2\sqrt{3x}+3}}{x^2-3}\) 3) \(\dfrac{\sqrt{x^2-5x+6}}{\sqrt{x-2}}\) 4)\(\dfrac{\sqrt{\left(x-4\right)^2}}{x^2-5x+4}\) 5) \(\dfrac{3x+1}{\sqrt{9x^2+6x+1}}\)
a,\(\sqrt{x^2+9}-\sqrt{x^2-x-3}=2\)
b,\(\sqrt{^3+1}+\sqrt{x^2+4x+3}=0\)
c,\(\sqrt[4]{5-x}+\sqrt[4]{x-1}=\sqrt{2}\)
d,\(\sqrt[3]{2+x+x^2}+\sqrt[3]{2-x-x^2}=\sqrt[3]{4}\)
e,\(4\sqrt{1-x}-1=3x+2\sqrt{1-x}+\sqrt{1-x^2}\)
f,\(\sqrt{\left(x-1\right)x}+\sqrt{\left(x-2\right)x}=\sqrt{\left(x+3\right)x}\)
Giải các phương trình sau:
a \(2\sqrt[3]{\left(x+2\right)^2}-\sqrt[3]{\left(x-2\right)^2}=\sqrt[3]{x^2-4}\)
b \(\sqrt[3]{\left(65+x\right)^2}+4\sqrt[3]{\left(65-x\right)^2}=5\sqrt[3]{65^2-x^2}\)
c \(\sqrt[3]{x+1}+\sqrt[3]{x+2}=1+\sqrt[3]{x^2+3x+2}\)
d \(\sqrt[3]{x-2}+\sqrt[3]{x+3}=\sqrt[3]{2x+1}\)
e \(\sqrt[3]{2x-1}+\sqrt[3]{x-1}=\sqrt[3]{3x+1}\)
Phương pháp 5. Biến đổi về dạng tổng các bình phương \(A^2+B^2+C^2=0\)
a \(x+y+12=4\sqrt{x}+6\sqrt{y-1}\)
b \(x+y+z+35=2\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)
c \(9x+17=6\sqrt{8x+1}+4\sqrt{x+3}\)
d \(\sqrt{x}+2\sqrt{x+3}=x+4\)
e\(\sqrt{3-x}+2\sqrt{3x-2}-3=x\)
1.\(x\sqrt{x+\sqrt{x}}-\sqrt{x-\sqrt{x}}=\frac{3}{2}\sqrt{\frac{x}{x+\sqrt{x}}}\)
2.\(\sqrt{x-2+\sqrt{2x-5}}+\sqrt{x+2+3\sqrt{2x-5}}=7\sqrt{2}\)
3.\(\sqrt[4]{x}+\sqrt[4]{17-x}=3\)
4.\(\sqrt[3]{x+1}-\sqrt[3]{x-1}=\sqrt[6]{x^2-1}\)
5.\(\sqrt[3]{2x-1}=x\sqrt[3]{16}-\sqrt[3]{2x+1}\)
1, \(\sqrt{x-1}+\sqrt{x-4}=5\)
2, \(2x-7\sqrt{x}+5=0\)
3, \(\sqrt{2x+1}+\sqrt{x-3}=2\sqrt{x}\)
4, \(x-4\sqrt{x}+2021\sqrt{x-4}+4=0\)
5, \(\sqrt{2x-3}-\sqrt{x+1}=7\left(4-x\right)\)