Question

\(\sqrt{3x-7}=4\)

Answer 1

\(\sqrt{3x-7}=4\)

\(\sqrt{\left(3x-7\right)^2}=4^2\) (ĐK: \(x\ge \)\(\dfrac{7}{3}\))

\(3x-7=16\)

\(3x=16+7=23\)

\(x=\dfrac{23}{3}\)

 

Answer 2

\(\sqrt{3x-7}=4\) (ĐK: \(x\ge\dfrac{7}{3}\))

\(\Leftrightarrow3x-7=4^2\)

\(\Leftrightarrow3x-7=16\)

\(\Leftrightarrow3x=16+7\)

\(\Leftrightarrow3x=23\)

\(\Leftrightarrow x=\dfrac{23}{3}\)

Answer 3

\(\sqrt[]{3x-4}=4\left(x\ge\dfrac{4}{3}\right)\)

\(\Rightarrow3x-7=16\Rightarrow3x=23\Rightarrow x=\dfrac{23}{3}\)