\(\dfrac{3}{4}< \dfrac{3+3}{4+3}=\dfrac{6}{7}\)
\(\dfrac{6}{7}< \dfrac{6+3}{7+3}< \dfrac{9}{10}\)
\(\dfrac{9}{10}< \dfrac{9+9}{10+9}=\dfrac{18}{19}\)
\(\dfrac{18}{19}< \dfrac{18+18}{19+18}=\dfrac{36}{37}\)
Vậy \(\dfrac{36}{37}>\dfrac{18}{19}>\dfrac{9}{10}>\dfrac{6}{7}>\dfrac{3}{4}\)
\(\dfrac{18}{19}=1-\dfrac{1}{19}\)
\(\dfrac{9}{10}=1-\dfrac{1}{10}\)
\(\dfrac{6}{7}=1-\dfrac{1}{7}\)
\(\dfrac{3}{4}=1-\dfrac{1}{4}\)
\(\dfrac{36}{37}=1-\dfrac{1}{37}\)
Do \(37>19>10>7>4\)
\(\Rightarrow\dfrac{1}{37}< \dfrac{1}{19}< \dfrac{1}{10}< \dfrac{1}{7}< \dfrac{1}{4}\)
\(\Rightarrow1-\dfrac{1}{37}>1-\dfrac{1}{19}>1-\dfrac{1}{10}>1-\dfrac{1}{7}>1-\dfrac{1}{4}\)
\(\Rightarrow\dfrac{36}{37}>\dfrac{18}{19}>\dfrac{9}{10}>\dfrac{6}{7}>\dfrac{3}{4}\)
