umk khong sao bài dk hok thêm ý mà ^-^
Ta có :
\(2009A=\frac{2009\left(2009^{2008}+1\right)}{2009^{2009}+1}=\frac{2009^{2009}+2009}{2009^{2009}+1}=1+\frac{2008}{2009^{2009}+1}\)
\(2009B=\frac{2009\left(2009^{2009}+1\right)}{2009^{2010}+1}=\frac{2009^{2010}+2009}{2009^{2010}+1}=1+\frac{2008}{2009^{2010}+1}\)
Vì \(1+\frac{2008}{2009^{2009}+1}>1+\frac{2008}{2009^{2010}+1}\Rightarrow2009A>2009B\)
=> A > B
\(\frac{2009^{2009}+1}{2009^{2010}+1}< \frac{2009^{2009}+1+2008}{2009^{2010}+1+2008}\)
\(=\frac{2009.\left(2009^{2008}+1\right)}{2009.\left(2009^{2009}+1\right)}\)
\(A< 1\)
\(\Rightarrow A< B\)
k minh nha minh dang can
2009A=\(\frac{2009\left(2009^{2008}+1\right)}{2009+1}=\frac{2009^{2009}+2009}{2009^{2009+1}}=1+\frac{2008}{2009^{2009}+1}\)
2009B=\(\frac{2009\left(2009^{2009}+1\right)}{2009^{2009}+1}=\frac{2009^{2010}+2009}{2009^{2010}+1}=1+\frac{2008}{2009^{2010}+1}\)
Vì 1+\(\frac{2008}{2009^{2009}+1}\)>1+\(\frac{2008}{2009^{2010}+1}\)
-->A>B
TK cho mk nha
A > B
Chúc bạn học tốt
Cách làm giống Đinh Đức Hùng
^.^
Mot tam bien quang cao hinh chu nhat co dien h 9 met vuong .Chieu rong la 12/5.Chu vi tam bien la...