đặt A=1+3+32+33+...+310
=>3A=3+32+33+34+...+311
=>3A-A=(3+32+33+34+...+311)-(1+3+32+33+...+310)
=>2A=311-1<311
Vậy 311>1+3+32+33+...+310
Đặt A = 1+3+32+33+...+310
Khi đó 3A = 3+32+33+34+...+311
=> 3A - A = (3+32+33+34+...+311) - (1+3+32+33+...+310)
=> 2A = 311 - 1 < 311
=> A < 311
Vậy 311 > 1+3+32+33+...+310