Question

S=2¹⁰⁰-2⁹⁹+2⁹⁸+...+2²-2

giúp tớ vs aaa

tớ cảm ơn

Answer 1

Sửa đề: \(S=2^{100}-2^{99}+2^{98}-...+2^2-2\)

=>\(2\cdot S=2^{101}-2^{100}+2^{99}-...+2^3-2^2\)

=>\(2S+S=2^{100}-2^{99}+2^{98}-...+2^2-2+2^{101}-2^{100}+2^{99}-...+2^3-2^2\)

=>\(3S=2^{101}-2\)

=>\(S=\dfrac{2^{101}-2}{3}\)

Answer 2

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