\(=\dfrac{\sqrt{x}\left(\sqrt{x}+2\right)}{\sqrt{x}}-3+\sqrt{x}\)
\(=\sqrt{x}+2-3+\sqrt{x}=2\sqrt{x}-1\)
ĐK: \(x>0\)
Khi đó:
\(P=\dfrac{\sqrt{x}\left(\sqrt{x}+2\right)}{\sqrt{x}}-3+\sqrt{x}\\ =\sqrt{x}+2-3+\sqrt{x}\\ =2\sqrt{x}-1\)
\(P=\dfrac{x+2\sqrt{x}}{\sqrt{x}}-\left(3-\sqrt{x}\right)\\ =\dfrac{\sqrt{x}\left(\sqrt{x}+2\right)}{\sqrt{x}}-\left(3-\sqrt{x}\right)\\ =\sqrt{x}+2-3+\sqrt{x}\\ =2\sqrt{x}-1\)