\(=\dfrac{2}{x-1}-\dfrac{x+1}{2\left(x-1\right)}+\dfrac{2x}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{4\left(x+1\right)-x^2-2x-1+4x}{2\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{4x+4-x^2+2x-1}{2\left(x-1\right)\left(x+1\right)}=\dfrac{-x^2+6x+3}{2\left(x-1\right)\left(x+1\right)}\)
Rút gọn
a) \((\dfrac{2x^2+3x}{x^3+1}+\dfrac{1}{x^2-x+1}).\dfrac{x^2-x+1}{x}\)
b) \(\left(\dfrac{1}{x-1}-\dfrac{1}{x}\right):\left(\dfrac{x+1}{x-2}-\dfrac{x+2}{x-1}\right)\)
c) \(\left(\dfrac{1}{x}+\dfrac{x}{x+1}\right).\dfrac{x^2+x}{x}\)
Rút gọn các biểu thức sau :
A = \(2x^2\left(-3x^3+2x^2+x-1\right)+2x\left(x^2-3x+1\right)\)
B = \(2x:\dfrac{1}{2}x+x^2\)
C = \(\left[1:\left(1+x\right)+2x:\left(1-x^2\right)\right]:\left(\dfrac{1}{x}-1\right)\)
D = \(\dfrac{x^2-y^2}{x+y}.\dfrac{\left(x+y\right)^2}{x}+\dfrac{y^2}{x+y}.\dfrac{\left(x+y\right)^2}{x}\)
E = \(\dfrac{\left|x-3\right|}{x^2-9}.\left(x^2+6x+9\right)\)
F = \(\dfrac{\sqrt{x}}{\sqrt{x}-5}-\dfrac{10\sqrt{x}}{x-25}-\dfrac{5}{\sqrt{x}+5}\)
P=\(\left(\dfrac{3\left(x+2\right)}{2x^2+8}-\dfrac{2x^2-x-10}{\left(x+1\right)\left[\left(x+1\right)^2-2x\right]}\right):\left(\dfrac{5}{x^2+1}+\dfrac{3}{2\left(x+1\right)}-\dfrac{3}{x-1}\right)\cdot\dfrac{2}{x-1}\)
a) rút gọn P
b)tìm tất cả các giá trị nguyên của x để P có giá trị là bội của 4
rút gọn
\(\dfrac{x^2}{x^2-1}+\dfrac{x}{\left(1-x\right)\left(x+1\right)}\)
\(\dfrac{3}{2x+6}-\dfrac{x-3}{x^2+3x}\)
\(\dfrac{1}{1-x}+\dfrac{2x}{x^2-1}\)
Rút gọn
a)\(\dfrac{x}{x+1}+\dfrac{1}{x-1}-\dfrac{2x}{1-x^2}\)
b)\(\dfrac{x}{x-2}-\dfrac{4x}{x^2-4}-\dfrac{2}{x+2}\)
c)\(\dfrac{2x^2-3x-9}{x^2-9}-\dfrac{x}{x+3}-\dfrac{x+3}{3-x}\)
d)\(\dfrac{x+3}{x-2}+\dfrac{x+2}{1-x}-\dfrac{4x-x^2}{x^2-3x+2}\)
giúp mik vs
cảm ơn <3
Rút gọn A= \(\dfrac{1}{x}\)-\(\dfrac{x}{2x+1}\)+\(\dfrac{2x^2-3x-1}{x\left(2x+1\right)}\) x≠0,\(\dfrac{1}{2}\),1
Help
M=\(\left(\dfrac{x^2-2x}{2x^2+8}-\dfrac{2x^2}{8-4x+2x^2-x^3}\right)\left(1-\dfrac{1}{x}-\dfrac{2}{x^2}\right)\)
a) tìm ĐKXĐ của x
b) rút gọn M
c) tìm x để M≥-3
rút gọn \(\dfrac{1}{x}\)-\(\dfrac{x}{2x+1}\)+\(\dfrac{2x^2-3x-1}{x\left(2x+1\right)}\)
A= \(\left(\dfrac{x+y}{y}-\dfrac{2y}{y-x}\right):\left(\dfrac{x^2+y^2}{y-x}\right)+\left(\dfrac{x^2+1}{2x-1}-\dfrac{x}{2}\right).\dfrac{1-2x}{x+2}\)
Với điều kiện của x, y để A có nghĩa, hãy rút gọn biểu thức trên
Rút gọn \(\left(\dfrac{1}{x-1}+2+\dfrac{2x^3+x^2-x}{1-x^3}\right):\dfrac{1-2x}{x^3+x-2}\)
