Question

Rút gọn 

Answer 1

b)

\(\dfrac{2x^2+4x+2}{4x\left(x+1\right)}=\dfrac{2\left(x^2+2x+1\right)}{4x\left(x+1\right)}=\dfrac{2\left(x+1\right)^2}{4x\left(x+1\right)}=\dfrac{x+1}{2x}\)

c)

\(\dfrac{2\left(x-y\right)}{y-x}=\dfrac{-2\left(y-x\right)}{y-x}=-2\)

Answer 2

b: \(=\dfrac{2\left(x^2+2x+1\right)}{4x\left(x+1\right)}=\dfrac{2\left(x+1\right)^2}{4x\left(x+1\right)}=\dfrac{x+1}{2x}\)

d: \(=\dfrac{-2\left(y-x\right)}{y-x}=-2\)