Question

Rút gọn:

Answer 1

c: \(=\left(2x-3-2x-3\right)^2=36\)

b: \(=9x^2-6x+1-2\left(9x^2+15x+3x+5\right)+9x^2+30x+25\)

\(=18x^2+24x+26-18x^2-36x-10=-12x+16\)

g: \(=\left(x^4-4\right)\left[\left(x^2+2\right)^2-4x^2\right]\)

\(=\left(x^4-4\right)\left(x^4+4\right)=x^8-16\)

Answer 2

Lời giải:
c.

$C=(2x-3)^2-2(4x^2-9)+(2x+3)^2$

$=(2x-3)^2-2(2x-3)(2x+3)+(2x+3)^2$
$=[(2x-3)-(2x+3)]^2=(-6)^2=36$

e.

$E=(3x-1)^2-2(3x-1)(3x+5)+(3x+5)^2$
$=[(3x-1)-(3x+5)]^2=(-6)^2=36$

g.

$G=(x^2-2x+2)(x^2-2)(x^2+2x+2)(x^2+2)$

$=[(x^2-2x+2)(x^2+2x+2)][(x^2-2)(x^2+2)]$

$=[(x^2+2)^2-(2x)^2](x^4-4)$

$=(x^4+4)(x^4-4)=x^8-16$