\(6\sqrt{2}+\dfrac{3\sqrt{2}}{2}-4\sqrt{2}-9\sqrt{2}\)
\(=\dfrac{\left(6+3-4-9\right)\sqrt{2}}{2}\)
=\(\dfrac{4\sqrt{2}}{2}=2\sqrt{2}\)
đây là ý a nha
\(=2\sqrt{3}-10\sqrt{3}-\sqrt{3}+\dfrac{10\sqrt{3}}{3}\)
=\(\dfrac{\left(2-10+10\right)\sqrt{3}}{3}=\dfrac{2\sqrt{3}}{3}\)
đây là ý b