Ta có: \(\left(\frac{3}{x-3}-\frac{2x}{9-x^2}+\frac{x}{x+3}\right):\frac{2x}{x+3}\)
\(=\frac{3\left(x+3\right)+2x+x\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}\cdot\frac{x+3}{2x}\)
\(=\frac{3x+9+2x+x^2-3x}{2x\left(x-3\right)}=\frac{x^2+2x+9}{2x\left(x-3\right)}\)




