Question

Phân tích thành nhân tử

(a+1)^2-(a-1)^2

(x+5)^2-x^2

(x+2)^2-9x^2

(3x+1)^2-(5x-1)^2

giúp em nhanh với ạ huhu

 

Answer 1

a: \(\left(a+1\right)^2-\left(a-1\right)^2\)

\(=\left(a+1-a+1\right)\left(a+1+a-1\right)\)

\(=4a\)

b: \(\left(x+5\right)^2-x^2\)

\(=\left(x+5-x\right)\left(x+5+x\right)\)

\(=5\left(2x+5\right)\)

Answer 2

1) \(\left(a+1\right)^2-\left(a-1\right)^2\)

= \(\left(a+1-a+1\right)\left(a+1+a-1\right)\)

= \(2.2a\)

=\(4a\)

2)\(\left(x+5\right)^2-x^2\)

=\(\left(x+5-x\right)\left(x+5+x\right)\)

=5.\(\left(2x+5\right)\)

3)\(\left(x+2\right)^2-9x^2\)

=\(\left(x+2\right)^2-\left(3x\right)^2\)

=\(\left(x+2-3x\right)\left(x+2+3x\right)\)

4)\(\left(3x+1\right)^2-\left(5x-1\right)^2\)

=\(\left(3x+1-5x+1\right)\left(3x+1+5x-1\right)\)

=\(\left(-2x+2\right).8x\)