Question

Bài 1:Phân tích đa thức thành nhân tử bằng phương pháp nhóm hạng tử

c, 3x^2-3xy-5x+5y

d, x^3-3x^2-4x+12

e, 45+x^3-5x^2-9x

Answer 1

\(3x^2-3xy-5x+5y=3x\left(x-y\right)-5\left(x-y\right)=\left(3x-5\right)\left(x-y\right)\\ x^3-3x^2-4x+12=x^2\left(x-3\right)-4\left(x-3\right)=\left(x-2\right)\left(x+2\right)\left(x-3\right)\\ 45+x^3-5x^2-9x=x^2\left(x-5\right)-9\left(x-5\right)=\left(x-3\right)\left(x+3\right)\left(x-5\right)\)

Answer 2

c)=3x(x-y)-5(x-y)

   =(3x-5)(x-y)

Answer 3

Bn j ơi gõ latex đi bn !

Answer 4

a) \(3x^2-3xy-5x+5y=3x\left(x-y\right)-5\left(x-y\right)=\left(x-y\right)\left(3x-5\right)\)

b) \(x^3-3x^2-4x+12=x^2\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x^2-4\right)=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

c) \(45+x^3-5x^2-9x=x^2\left(x-5\right)-9\left(x-5\right)=\left(x-5\right)\left(x^2-9\right)=\left(x-5\right)\left(x-3\right)\left(x+3\right)\)

Answer 5

c: \(3x^2-3xy-5x+5y\)

\(=3x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(3x-5\right)\)

d: \(x^3-3x^2-4x+12\)

\(=x^2\left(x-3\right)-4\left(x-3\right)\)

\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

e: \(x^3-5x^2-9x+45\)

\(=x^2\left(x-5\right)-9\left(x-5\right)\)

\(=\left(x-5\right)\left(x-3\right)\left(x+3\right)\)